A photograph with length $L$ and width $W$ is placed in a mat of width 8 centimeters $(\mathrm{cm})$. The area of the mat (in square centimeters, or $\mathrm{cm}^{2}$ ) is found to be $A=(L+16)(W+16)-L \cdot W .$

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A photograph with length $L$ and width $W$ is placed in a mat of width 8 centimeters $(\mathrm{cm})$. The area of the mat (in square centimeters, or $\mathrm{cm}^{2}$ ) is found to be $A=(L+16)(W+16)-L \cdot W .$

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A photograph with length $L$ and width $W$ is placed in a mat of width 8 centimeters $(\mathrm{cm})$. The area of the mat (in square centimeters, or $\mathrm{cm}^{2}$ ) is found to be $A=(L+16)(W+16)-L \cdot W .$

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