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arrow_back SImplify $\dfrac{1+\cot ^{2} \theta}{\sec ^{2} \theta}$

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SImplify $\dfrac{1+\cot ^{2} \theta}{\sec ^{2} \theta}$

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$\dfrac{\csc ^{2} \theta}{\sec ^{2} \theta}=\frac{\dfrac{1}{\sin ^{2} \theta}}{\frac{1}{\cos ^{2} \theta}}=\dfrac{\cos ^{2} \theta}{\sin ^{2} \theta}=\cot ^{2} x$
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