arrow_back Solve the inequality $\frac{7}{3}<\frac{p}{3}$

66 views
Solve the inequality $\dfrac{7}{3}<\dfrac{p}{3}$

Step 1. Swap sides
$\frac{7}{3}<\frac{p}{3}$
Swap sides:
$\frac{p}{3}>\frac{7}{3}$

Step 2. Isolate the $p$
$\frac{p}{3}>\frac{7}{3}$
Multiply to both sides by 3 :
$\frac{p}{3} \cdot 3>\frac{7}{3} \cdot 3$
Group like terms:
$\frac{1}{3} \cdot 3 p>\frac{7}{3} \cdot 3$
Simplify the fraction:
$p>\frac{7}{3} \cdot 3$
Multiply the fractions:
$p>\frac{7 \cdot 3}{3}$
Simplify the right side:
$p>7$

Step 3. Solution on a coordinate plane

Solution:
$p>7$
Interval notation:
$(7, \infty)$

by Gold Status
(31,957 points)

Related questions

Notice: Undefined index: avatar in /home/customer/www/mathsgee.com/public_html/qa-theme/AVEN/qa-theme.php on line 993
Solve the following inequality. Write the solution set in interval notation. $$2 \geq \frac{5-3 x}{4}>-3$$
Solve the following inequality. Write the solution set in interval notation. $$2 \geq \frac{5-3 x}{4}>-3$$Solve the following inequality. Write the solution set in interval notation. $$2 \geq \frac{5-3 x}{4}&gt;-3$$ ...
close

Notice: Undefined index: avatar in /home/customer/www/mathsgee.com/public_html/qa-theme/AVEN/qa-theme.php on line 993
Solve the following quadratic inequality. Write the solution set in interval notation. $$x^{2}-2 x-35<0$$
Solve the following quadratic inequality. Write the solution set in interval notation. $$x^{2}-2 x-35<0$$Solve the following quadratic inequality. Write the solution set in interval notation. $$x^{2}-2 x-35&lt;0$$ ...
close

Notice: Undefined index: avatar in /home/customer/www/mathsgee.com/public_html/qa-theme/AVEN/qa-theme.php on line 993
Solve the following rational inequality. Write the solution set in interval notation. $$\frac{x+9}{x-6} \leq 0$$
Solve the following rational inequality. Write the solution set in interval notation. $$\frac{x+9}{x-6} \leq 0$$Solve the following rational inequality. Write the solution set in interval notation. $$\frac{x+9}{x-6} \leq 0$$ ...
close

Notice: Undefined index: avatar in /home/customer/www/mathsgee.com/public_html/qa-theme/AVEN/qa-theme.php on line 993
Solve the following inequality. Write the solution set in interval notation. $$2 x+1 \leq 3 x-2$$
Solve the following inequality. Write the solution set in interval notation. $$2 x+1 \leq 3 x-2$$Solve the following inequality. Write the solution set in interval notation. $$2 x+1 \leq 3 x-2$$ ...
close

Notice: Undefined index: avatar in /home/customer/www/mathsgee.com/public_html/qa-theme/AVEN/qa-theme.php on line 993
Solve for $x$ in $\frac{2}{a+1}-\frac{1}{3} \leq 5$ (represent your final answer in interval notation)
Solve for $x$ in $\frac{2}{a+1}-\frac{1}{3} \leq 5$ (represent your final answer in interval notation)Solve for $x$ in $\dfrac{2}{a+1}-\dfrac{1}{3} \leq 5$ (represent your final answer in interval notation) ...
close

Notice: Undefined index: avatar in /home/customer/www/mathsgee.com/public_html/qa-theme/AVEN/qa-theme.php on line 993
Solve $\frac{x}{2}+\frac{x}{3}=5$
Solve $\frac{x}{2}+\frac{x}{3}=5$Solve $\dfrac{x}{2}+\dfrac{x}{3}=5$ ...
close

Notice: Undefined index: avatar in /home/customer/www/mathsgee.com/public_html/qa-theme/AVEN/qa-theme.php on line 993
Given: $-4 \leq-\frac{1}{2} m<5$ where $m \in R$, solve for $m$, write the answer in interval notation.
Given: $-4 \leq-\frac{1}{2} m<5$ where $m \in R$, solve for $m$, write the answer in interval notation.Given: $-4 \leq-\frac{1}{2} m&lt;5$ where $m \in R$, solve for $m$, write the answer in interval notation. ...
close

Notice: Undefined index: avatar in /home/customer/www/mathsgee.com/public_html/qa-theme/AVEN/qa-theme.php on line 993
Solve the inequality $(1-x)(x+2)<0$
Solve the inequality $(1-x)(x+2)<0$Solve the inequality $(1-x)(x+2)&lt;0$ ...
close

Notice: Undefined index: avatar in /home/customer/www/mathsgee.com/public_html/qa-theme/AVEN/qa-theme.php on line 993
Solve $2(x-1)>3(2 x+3)$
Solve $2(x-1)>3(2 x+3)$Solve $2(x-1)&gt;3(2 x+3)$ ...
close

Notice: Undefined index: avatar in /home/customer/www/mathsgee.com/public_html/qa-theme/AVEN/qa-theme.php on line 993
Describe the set or the resulting set using the roster method. Solve for ${x|x+9=−4}$
Describe the set or the resulting set using the roster method. Solve for ${x|x+9=−4}$Describe the set or the resulting set using the roster method. Solve for $\{x|x+9=−4\}$ ...
close

Notice: Undefined index: avatar in /home/customer/www/mathsgee.com/public_html/qa-theme/AVEN/qa-theme.php on line 993
Solve the following absolute value inequality. $$|5 x-3| \geq-1$$
Solve the following absolute value inequality. $$|5 x-3| \geq-1$$Solve the following absolute value inequality. $$|5 x-3| \geq-1$$ ...
close

Notice: Undefined index: avatar in /home/customer/www/mathsgee.com/public_html/qa-theme/AVEN/qa-theme.php on line 993
Solve $t^{3} \frac{d x}{d t}+3 t^{2} x=t, \quad x(2)=0$
Solve $t^{3} \frac{d x}{d t}+3 t^{2} x=t, \quad x(2)=0$Solve $t^{3} \frac{d x}{d t}+3 t^{2} x=t, \quad x(2)=0$ ...
close

Notice: Undefined index: avatar in /home/customer/www/mathsgee.com/public_html/qa-theme/AVEN/qa-theme.php on line 993
Solve for $x$ in $\frac{3 x-2}{2}=x+1$
Solve for $x$ in $\frac{3 x-2}{2}=x+1$Solve for $x$ in $\frac{3 x-2}{2}=x+1$ ...
Convert $\frac{d^{3} x}{d t^{3}}+x=0$ to a first-order differential equation. Solve this equation over the interval $[0,1]$ for the initial conditions $x^{\prime \prime}(0)=0, x^{\prime}(0)=1$, and $x(0)=0$.Convert $\frac{d^{3} x}{d t^{3}}+x=0$ to a first-order differential equation. Solve this equation over the interval $0,1$ for the initial conditions ...
For positive reals $a, b, c$, show that $$\frac{a^{2}}{b c}+\frac{b^{2}}{c a}+\frac{c^{2}}{a b} \geq 3 .$$
For positive reals $a, b, c$, show that $$\frac{a^{2}}{b c}+\frac{b^{2}}{c a}+\frac{c^{2}}{a b} \geq 3 .$$For positive reals $a, b, c$, show that $$\frac{a^{2}}{b c}+\frac{b^{2}}{c a}+\frac{c^{2}}{a b} \geq 3 .$$ ...